这段时间一直都在研究jsp生成静态页面的方法，在网上找了很多资料，也有不少朋友给我提出解决方案，确实解决了不少的问题，但是这样做有点麻烦。其实我并不是想减轻服务器的压力，我们要做的不是门户网站，访问量没那么大，所以不用担心服务器的承受能力。只是希望搜索引擎能够搜索到我们的页面，只要能达到目的，用什么样的方式都可以。
在网上看到了一则URL重写的贴子，感觉比较适合我这样的情况，应用起来简单。然后自己试着写了一个例子，居然成功了，而在Struts里不知道怎么实现，实现转发的时候好象没什么用了。*.do好象不能实现映射
以下是相关代码，若有不正之处，欢迎大家指正!
首先要去下载一个urlrewritefilter-2.6.zip,然后把它解压到WEB-INF下，然后配置一下web.xml
xml version="1.0" encoding="UTF-8"?><web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <filter> <filter-name>UrlRewriteFilterfilter-name> <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilterfilter-class> <init-param> <param-name>logLevelparam-name> <param-value>WARNparam-value> init-param> filter> <filter-mapping> <filter-name>UrlRewriteFilterfilter-name> <url-pattern>/*url-pattern> filter-mapping> <servlet> <servlet-name>actionservlet-name> <servlet-class>org.apache.struts.action.ActionServletservlet-class> <init-param> <param-name>configparam-name> <param-value>/WEB-INF/struts-config.xmlparam-value> init-param> <init-param> <param-name>debugparam-name> <param-value>3param-value> init-param> <init-param> <param-name>detailparam-name> <param-value>3param-value> init-param> <load-on-startup>0load-on-startup> servlet> <servlet-mapping> <servlet-name>actionservlet-name> <url-pattern>*.dourl-pattern> servlet-mapping>web-app>
然后再随便建立几个jsp页面，如：
MyJsp.jsp
<%@ page language="java" import="java.util.*" pageEncoding="GBK"%><%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%>DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> <head> <base href="<%=basePath%>"> <title>My JSP "MyJsp.jsp" starting pagetitle> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> head> <body> <% String a = request.getParameter("id"); %> <%=basePath %> <br> <% if(a.equals("123")) { out.println("哈哈"); } else { out.println("再试一次!"); } %> body>html>接着在urlrewrite.xml里配置一下路径
xml version="1.0" encoding="utf-8"?>DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN" "http://tuckey.org/res/dtds/urlrewrite2.6.dtd"><urlrewrite> <rule> <note> The rule means that requests to /test/status/ will be redirected to /rewrite-status the url will be rewritten. note> <from>/test/status/from> <to type="redirect">%{context-path}/rewrite-statusto> rule> <outbound-rule> <note> The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url) the url /rewrite-status will be rewritten to /test/status/. The above rule and this outbound-rule means that end users should never see the url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks in your pages. note> <from>/rewrite-statusfrom> <to>/test/status/to> outbound-rule> <rule> <from>/test/([0-9]+)from> <to>/MyJsp.jsp?id=$1to> rule>urlrewrite>启动服务器，然后输入http://localhost:8080/test/123 ,那么就可以显示了,而实际上读取的路径是http://localhost:8080/MyJsp.jsp?id=123
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